https://www.emarazzak.blogspot.com

Tuesday, March 3, 2015

Basic Electrical Engineering



Series circuits:

Series circuits are sometimes called current-coupled or daisy chain-coupled. The current in a series circuit goes through every component in the circuit. Therefore, all of the components in a series connection carry the same current. There is only one path in a series circuit in which the current can flow.
A series circuit's main disadvantage or advantage, depending on its intended role in a product's overall design, is that because there is only one path in which its current can flow, opening or breaking a series circuit at any point causes the entire circuit to "open" or stop operating. For example, if even one of the light bulbs in an older-style string of Christmas tree lights burns out or is removed, the entire string becomes inoperable until the bulb is replaced.

Current

I = I_1 = I_2 = \dots = I_n
In a series circuit the current is the same for all elements.

Resistors

The total resistance of resistors in series is equal to the sum of their individual resistances:
This is a diagram of several resistors, connected end to end, with the same amount of current through each.
R_\mathrm{total} = R_1 + R_2 + \cdots + R_n
Electrical conductance presents a reciprocal quantity to resistance. Total conductance of a series circuits of pure resistors, therefore, can be calculated from the following expression:
\frac{1}{G_\mathrm{total}} = \frac{1}{G_1} + \frac{1}{G_2} + \cdots + \frac{1}{G_n}.
For a special case of two resistors in series, the total conductance is equal to:
G_{total} = \frac{G_1 G_2}{G_1+G_2}.

 



Tuesday, February 24, 2015





DEPARTMENT OF CIVIL ENGINEERING 
Program: B. Sc in Civil Engineering
Course Title:
Mechanics, Heat, Thermodynamics, Waves, Oscillations and Physical Optics- Lab
Course code:        PHY 103
Assignment
Experiment No-01                                   Experiment Done Date: 28.01.2015
Name of the Experiment:
To determine the focal length and hence the power of a convex lens by displacement method with the help of an optical bench.
Submitted by:
Name: Mohammed Abdur Razzak
Roll No:  3326,  Registration No: WUB/10/13/60/3326, 
Batch No: 60/C, Semester No: Fourth, Year: Second.

Submitted To:
Name:  Md. Shohel Rana
 Designation:  Lecturer in physics, Basic science Division (WUB)                 Date of Submission:
Experiment No.:04
Experiment Name: Determine the focal length and hence the power of a convex lens by displacement method with the help of an optical bench.
Theory: If the object and the image screen be so placed on an optical bench that the distance between them is greater than four times the focal length (f) of a given convex lens, then there will be two different positions of the lens which for which an equal sharp image will be obtained on the image screen.
                                                                                                                     
The fig represent respectively the positions of the object and the image screen and the two different positions of the lens for which an equally sharp image is obtained.
Let the distance Ol =D and L1 – L2 = x.
From the lens equation , we have
Or,   (since u + v =D)
Applying sign convention, u is negative.
Or,
Or, u2 – ud =df = 0
Solving the above equation which is quartic, we have two values of u corresponding to the two positions of the lens. These are

u1 =  -  position L1 of the lens

And u2 =  +  position L2 of the lens
Then x = L1  L2 = u1  u2 =
Or   x2 = D2 – 4Df
Or   f =  ……………….. (1)


Where D is the distance between the object and the image and must be greater than 4f and x is the distance between two different positions of the lens.
The power P of the lens s as usual given by the relation,
P =  diopters

Results:


Table I
No. of obs.
Position of
Displacement of Lens
X = L1 – L2
(cm)
Apparent distance between object and image
D’ = O
Corrected distance between object and image
D = D’ +
Object
(O)
Image
(I)
Lens at
L1
L2
1
0
45
16
28.2
12.20
45

2
0
50
14.4
34.4
20.00
50

3
0
55
14
40.30
26.30
55

4
0
60
12.4
46.00
33.60
60

5
0
65
12.1
51.00
38.90
65



Table II:
No. of obs.
Lens displacement (x) from Tab. II
Corrected Distance (d) from Tab. II
Focal length
Mean focal length (f) cm
Power
P =
1
12.20
45
10.42
10.45
9.56
2
20.00
50
10.50
3
26.30
55
10.60
4
33.60
60
10.30
5
38.90
65
10.43

Your Secrecy